t^2-5t+10=0

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Solution for t^2-5t+10=0 equation:


Simplifying
t2 + -5t + 10 = 0

Reorder the terms:
10 + -5t + t2 = 0

Solving
10 + -5t + t2 = 0

Solving for variable 't'.

Begin completing the square.

Move the constant term to the right:

Add '-10' to each side of the equation.
10 + -5t + -10 + t2 = 0 + -10

Reorder the terms:
10 + -10 + -5t + t2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -5t + t2 = 0 + -10
-5t + t2 = 0 + -10

Combine like terms: 0 + -10 = -10
-5t + t2 = -10

The t term is -5t.  Take half its coefficient (-2.5).
Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.
-5t + 6.25 + t2 = -10 + 6.25

Reorder the terms:
6.25 + -5t + t2 = -10 + 6.25

Combine like terms: -10 + 6.25 = -3.75
6.25 + -5t + t2 = -3.75

Factor a perfect square on the left side:
(t + -2.5)(t + -2.5) = -3.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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